Metamath Proof Explorer


Theorem inrot

Description: Rotate the intersection of 3 classes. (Contributed by NM, 27-Aug-2012)

Ref Expression
Assertion inrot ( ( 𝐴 ∩ 𝐵 ) ∩ 𝐶 ) = ( ( 𝐶 ∩ 𝐴 ) ∩ 𝐵 )

Proof

Step Hyp Ref Expression
1 in31 ⊢ ( ( 𝐴 ∩ 𝐵 ) ∩ 𝐶 ) = ( ( 𝐶 ∩ 𝐵 ) ∩ 𝐴 )
2 in32 ⊢ ( ( 𝐶 ∩ 𝐵 ) ∩ 𝐴 ) = ( ( 𝐶 ∩ 𝐴 ) ∩ 𝐵 )
3 1 2 eqtri ⊢ ( ( 𝐴 ∩ 𝐵 ) ∩ 𝐶 ) = ( ( 𝐶 ∩ 𝐴 ) ∩ 𝐵 )