Metamath Proof Explorer


Theorem intminss

Description: Under subset ordering, the intersection of a restricted class abstraction is less than or equal to any of its members. (Contributed by NM, 7-Sep-2013)

Ref Expression
Hypothesis intminss.1 ⊢ ( 𝑥 = 𝐴 → ( 𝜑 ↔ 𝜓 ) )
Assertion intminss ( ( 𝐴 ∈ 𝐵 ∧ 𝜓 ) → ∩ { 𝑥 ∈ 𝐵 ∣ 𝜑 } ⊆ 𝐴 )

Proof

Step Hyp Ref Expression
1 intminss.1 ⊢ ( 𝑥 = 𝐴 → ( 𝜑 ↔ 𝜓 ) )
2 1 elrab ⊢ ( 𝐴 ∈ { 𝑥 ∈ 𝐵 ∣ 𝜑 } ↔ ( 𝐴 ∈ 𝐵 ∧ 𝜓 ) )
3 intss1 ⊢ ( 𝐴 ∈ { 𝑥 ∈ 𝐵 ∣ 𝜑 } → ∩ { 𝑥 ∈ 𝐵 ∣ 𝜑 } ⊆ 𝐴 )
4 2 3 sylbir ⊢ ( ( 𝐴 ∈ 𝐵 ∧ 𝜓 ) → ∩ { 𝑥 ∈ 𝐵 ∣ 𝜑 } ⊆ 𝐴 )