Metamath Proof Explorer


Theorem intnand

Description: Introduction of conjunct inside of a contradiction. (Contributed by NM, 10-Jul-2005)

Ref Expression
Hypothesis intnand.1 ( 𝜑 → ¬ 𝜓 )
Assertion intnand ( 𝜑 → ¬ ( 𝜒𝜓 ) )

Proof

Step Hyp Ref Expression
1 intnand.1 ( 𝜑 → ¬ 𝜓 )
2 simpr ( ( 𝜒𝜓 ) → 𝜓 )
3 1 2 nsyl ( 𝜑 → ¬ ( 𝜒𝜓 ) )