Metamath Proof Explorer


Theorem iotabidv

Description: Formula-building deduction for iota. (Contributed by NM, 20-Aug-2011)

Ref Expression
Hypothesis iotabidv.1 ( 𝜑 → ( 𝜓𝜒 ) )
Assertion iotabidv ( 𝜑 → ( ℩ 𝑥 𝜓 ) = ( ℩ 𝑥 𝜒 ) )

Proof

Step Hyp Ref Expression
1 iotabidv.1 ( 𝜑 → ( 𝜓𝜒 ) )
2 1 alrimiv ( 𝜑 → ∀ 𝑥 ( 𝜓𝜒 ) )
3 iotabi ( ∀ 𝑥 ( 𝜓𝜒 ) → ( ℩ 𝑥 𝜓 ) = ( ℩ 𝑥 𝜒 ) )
4 2 3 syl ( 𝜑 → ( ℩ 𝑥 𝜓 ) = ( ℩ 𝑥 𝜒 ) )