Metamath Proof Explorer


Theorem ipffn

Description: The inner product operation is a function. (Contributed by Mario Carneiro, 20-Sep-2015)

Ref Expression
Hypotheses ipffn.1 ⊢ 𝑉 = ( Base ‘ 𝑊 )
ipffn.2 ⊢ , = ( ·if ‘ 𝑊 )
Assertion ipffn , Fn ( 𝑉 × 𝑉 )

Proof

Step Hyp Ref Expression
1 ipffn.1 ⊢ 𝑉 = ( Base ‘ 𝑊 )
2 ipffn.2 ⊢ , = ( ·if ‘ 𝑊 )
3 eqid ⊢ ( ·𝑖 ‘ 𝑊 ) = ( ·𝑖 ‘ 𝑊 )
4 1 3 2 ipffval ⊢ , = ( 𝑥 ∈ 𝑉 , 𝑦 ∈ 𝑉 ↦ ( 𝑥 ( ·𝑖 ‘ 𝑊 ) 𝑦 ) )
5 ovex ⊢ ( 𝑥 ( ·𝑖 ‘ 𝑊 ) 𝑦 ) ∈ V
6 4 5 fnmpoi ⊢ , Fn ( 𝑉 × 𝑉 )