Metamath Proof Explorer


Theorem isgrpd2

Description: Deduce a group from its properties. N (negative) is normally dependent on x i.e. read it as N ( x ) . Note: normally we don't use a ph antecedent on hypotheses that name structure components, since they can be eliminated with eqid , but we make an exception for theorems such as isgrpd2 , ismndd , and islmodd since theorems using them often rewrite the structure components. (Contributed by NM, 10-Aug-2013)

Ref Expression
Hypotheses isgrpd2.b ( 𝜑𝐵 = ( Base ‘ 𝐺 ) )
isgrpd2.p ( 𝜑+ = ( +g𝐺 ) )
isgrpd2.z ( 𝜑0 = ( 0g𝐺 ) )
isgrpd2.g ( 𝜑𝐺 ∈ Mnd )
isgrpd2.n ( ( 𝜑𝑥𝐵 ) → 𝑁𝐵 )
isgrpd2.j ( ( 𝜑𝑥𝐵 ) → ( 𝑁 + 𝑥 ) = 0 )
Assertion isgrpd2 ( 𝜑𝐺 ∈ Grp )

Proof

Step Hyp Ref Expression
1 isgrpd2.b ( 𝜑𝐵 = ( Base ‘ 𝐺 ) )
2 isgrpd2.p ( 𝜑+ = ( +g𝐺 ) )
3 isgrpd2.z ( 𝜑0 = ( 0g𝐺 ) )
4 isgrpd2.g ( 𝜑𝐺 ∈ Mnd )
5 isgrpd2.n ( ( 𝜑𝑥𝐵 ) → 𝑁𝐵 )
6 isgrpd2.j ( ( 𝜑𝑥𝐵 ) → ( 𝑁 + 𝑥 ) = 0 )
7 oveq1 ( 𝑦 = 𝑁 → ( 𝑦 + 𝑥 ) = ( 𝑁 + 𝑥 ) )
8 7 eqeq1d ( 𝑦 = 𝑁 → ( ( 𝑦 + 𝑥 ) = 0 ↔ ( 𝑁 + 𝑥 ) = 0 ) )
9 8 rspcev ( ( 𝑁𝐵 ∧ ( 𝑁 + 𝑥 ) = 0 ) → ∃ 𝑦𝐵 ( 𝑦 + 𝑥 ) = 0 )
10 5 6 9 syl2anc ( ( 𝜑𝑥𝐵 ) → ∃ 𝑦𝐵 ( 𝑦 + 𝑥 ) = 0 )
11 1 2 3 4 10 isgrpd2e ( 𝜑𝐺 ∈ Grp )