Metamath Proof Explorer


Theorem islpln2ah

Description: The predicate "is a lattice plane" for join of atoms. Version of islpln2a expressed with an abbreviation hypothesis. (Contributed by NM, 30-Jul-2012)

Ref Expression
Hypotheses islpln2a.l ⊢ ≤ = ( le ‘ 𝐾 )
islpln2a.j ⊢ ∨ = ( join ‘ 𝐾 )
islpln2a.a ⊢ 𝐴 = ( Atoms ‘ 𝐾 )
islpln2a.p ⊢ 𝑃 = ( LPlanes ‘ 𝐾 )
islpln2a.y ⊢ 𝑌 = ( ( 𝑄 ∨ 𝑅 ) ∨ 𝑆 )
Assertion islpln2ah ( ( 𝐾 ∈ HL ∧ ( 𝑄 ∈ 𝐴 ∧ 𝑅 ∈ 𝐴 ∧ 𝑆 ∈ 𝐴 ) ) → ( 𝑌 ∈ 𝑃 ↔ ( 𝑄 ≠ 𝑅 ∧ ¬ 𝑆 ≤ ( 𝑄 ∨ 𝑅 ) ) ) )

Proof

Step Hyp Ref Expression
1 islpln2a.l ⊢ ≤ = ( le ‘ 𝐾 )
2 islpln2a.j ⊢ ∨ = ( join ‘ 𝐾 )
3 islpln2a.a ⊢ 𝐴 = ( Atoms ‘ 𝐾 )
4 islpln2a.p ⊢ 𝑃 = ( LPlanes ‘ 𝐾 )
5 islpln2a.y ⊢ 𝑌 = ( ( 𝑄 ∨ 𝑅 ) ∨ 𝑆 )
6 5 eleq1i ⊢ ( 𝑌 ∈ 𝑃 ↔ ( ( 𝑄 ∨ 𝑅 ) ∨ 𝑆 ) ∈ 𝑃 )
7 1 2 3 4 islpln2a ⊢ ( ( 𝐾 ∈ HL ∧ ( 𝑄 ∈ 𝐴 ∧ 𝑅 ∈ 𝐴 ∧ 𝑆 ∈ 𝐴 ) ) → ( ( ( 𝑄 ∨ 𝑅 ) ∨ 𝑆 ) ∈ 𝑃 ↔ ( 𝑄 ≠ 𝑅 ∧ ¬ 𝑆 ≤ ( 𝑄 ∨ 𝑅 ) ) ) )
8 6 7 bitrid ⊢ ( ( 𝐾 ∈ HL ∧ ( 𝑄 ∈ 𝐴 ∧ 𝑅 ∈ 𝐴 ∧ 𝑆 ∈ 𝐴 ) ) → ( 𝑌 ∈ 𝑃 ↔ ( 𝑄 ≠ 𝑅 ∧ ¬ 𝑆 ≤ ( 𝑄 ∨ 𝑅 ) ) ) )