Metamath Proof Explorer


Theorem isperf

Description: Definition of a perfect space. (Contributed by Mario Carneiro, 24-Dec-2016)

Ref Expression
Hypothesis lpfval.1 𝑋 = 𝐽
Assertion isperf ( 𝐽 ∈ Perf ↔ ( 𝐽 ∈ Top ∧ ( ( limPt ‘ 𝐽 ) ‘ 𝑋 ) = 𝑋 ) )

Proof

Step Hyp Ref Expression
1 lpfval.1 𝑋 = 𝐽
2 fveq2 ( 𝑗 = 𝐽 → ( limPt ‘ 𝑗 ) = ( limPt ‘ 𝐽 ) )
3 unieq ( 𝑗 = 𝐽 𝑗 = 𝐽 )
4 3 1 eqtr4di ( 𝑗 = 𝐽 𝑗 = 𝑋 )
5 2 4 fveq12d ( 𝑗 = 𝐽 → ( ( limPt ‘ 𝑗 ) ‘ 𝑗 ) = ( ( limPt ‘ 𝐽 ) ‘ 𝑋 ) )
6 5 4 eqeq12d ( 𝑗 = 𝐽 → ( ( ( limPt ‘ 𝑗 ) ‘ 𝑗 ) = 𝑗 ↔ ( ( limPt ‘ 𝐽 ) ‘ 𝑋 ) = 𝑋 ) )
7 df-perf Perf = { 𝑗 ∈ Top ∣ ( ( limPt ‘ 𝑗 ) ‘ 𝑗 ) = 𝑗 }
8 6 7 elrab2 ( 𝐽 ∈ Perf ↔ ( 𝐽 ∈ Top ∧ ( ( limPt ‘ 𝐽 ) ‘ 𝑋 ) = 𝑋 ) )