Theorem isrim

Description: An isomorphism of rings is a bijective homomorphism. (Contributed by AV, 22-Oct-2019) Remove sethood antecedent. (Revised by SN, 12-Jan-2025)

	Ref	Expression
Hypotheses	rhmf1o.b	⊢ 𝐵 = ( Base ‘ 𝑅 )
	rhmf1o.c	⊢ 𝐶 = ( Base ‘ 𝑆 )
Assertion	isrim	⊢ ( 𝐹 ∈ ( 𝑅 RingIso 𝑆 ) ↔ ( 𝐹 ∈ ( 𝑅 RingHom 𝑆 ) ∧ 𝐹 : 𝐵 –1-1-onto→ 𝐶 ) )

Proof

Step	Hyp	Ref	Expression
1		rhmf1o.b	⊢ 𝐵 = ( Base ‘ 𝑅 )
2		rhmf1o.c	⊢ 𝐶 = ( Base ‘ 𝑆 )
3		isrim0	⊢ ( 𝐹 ∈ ( 𝑅 RingIso 𝑆 ) ↔ ( 𝐹 ∈ ( 𝑅 RingHom 𝑆 ) ∧ ◡ 𝐹 ∈ ( 𝑆 RingHom 𝑅 ) ) )
4	1 2	rhmf1o	⊢ ( 𝐹 ∈ ( 𝑅 RingHom 𝑆 ) → ( 𝐹 : 𝐵 –1-1-onto→ 𝐶 ↔ ◡ 𝐹 ∈ ( 𝑆 RingHom 𝑅 ) ) )
5	4	bicomd	⊢ ( 𝐹 ∈ ( 𝑅 RingHom 𝑆 ) → ( ◡ 𝐹 ∈ ( 𝑆 RingHom 𝑅 ) ↔ 𝐹 : 𝐵 –1-1-onto→ 𝐶 ) )
6	5	pm5.32i	⊢ ( ( 𝐹 ∈ ( 𝑅 RingHom 𝑆 ) ∧ ◡ 𝐹 ∈ ( 𝑆 RingHom 𝑅 ) ) ↔ ( 𝐹 ∈ ( 𝑅 RingHom 𝑆 ) ∧ 𝐹 : 𝐵 –1-1-onto→ 𝐶 ) )
7	3 6	bitri	⊢ ( 𝐹 ∈ ( 𝑅 RingIso 𝑆 ) ↔ ( 𝐹 ∈ ( 𝑅 RingHom 𝑆 ) ∧ 𝐹 : 𝐵 –1-1-onto→ 𝐶 ) )