Metamath Proof Explorer


Theorem isuvtx

Description: The set of all universal vertices. (Contributed by Alexander van der Vekens, 12-Oct-2017) (Revised by AV, 30-Oct-2020) (Revised by AV, 14-Feb-2022)

Ref Expression
Hypotheses uvtxel.v ⊢ 𝑉 = ( Vtx ‘ 𝐺 )
isuvtx.e ⊢ 𝐸 = ( Edg ‘ 𝐺 )
Assertion isuvtx ( UnivVtx ‘ 𝐺 ) = { 𝑣 ∈ 𝑉 ∣ ∀ 𝑘 ∈ ( 𝑉 ∖ { 𝑣 } ) ∃ 𝑒 ∈ 𝐸 { 𝑘 , 𝑣 } ⊆ 𝑒 }

Proof

Step Hyp Ref Expression
1 uvtxel.v ⊢ 𝑉 = ( Vtx ‘ 𝐺 )
2 isuvtx.e ⊢ 𝐸 = ( Edg ‘ 𝐺 )
3 1 uvtxval ⊢ ( UnivVtx ‘ 𝐺 ) = { 𝑣 ∈ 𝑉 ∣ ∀ 𝑘 ∈ ( 𝑉 ∖ { 𝑣 } ) 𝑘 ∈ ( 𝐺 NeighbVtx 𝑣 ) }
4 1 2 nbgrel ⊢ ( 𝑘 ∈ ( 𝐺 NeighbVtx 𝑣 ) ↔ ( ( 𝑘 ∈ 𝑉 ∧ 𝑣 ∈ 𝑉 ) ∧ 𝑘 ≠ 𝑣 ∧ ∃ 𝑒 ∈ 𝐸 { 𝑣 , 𝑘 } ⊆ 𝑒 ) )
5 df-3an ⊢ ( ( ( 𝑘 ∈ 𝑉 ∧ 𝑣 ∈ 𝑉 ) ∧ 𝑘 ≠ 𝑣 ∧ ∃ 𝑒 ∈ 𝐸 { 𝑣 , 𝑘 } ⊆ 𝑒 ) ↔ ( ( ( 𝑘 ∈ 𝑉 ∧ 𝑣 ∈ 𝑉 ) ∧ 𝑘 ≠ 𝑣 ) ∧ ∃ 𝑒 ∈ 𝐸 { 𝑣 , 𝑘 } ⊆ 𝑒 ) )
6 4 5 bitri ⊢ ( 𝑘 ∈ ( 𝐺 NeighbVtx 𝑣 ) ↔ ( ( ( 𝑘 ∈ 𝑉 ∧ 𝑣 ∈ 𝑉 ) ∧ 𝑘 ≠ 𝑣 ) ∧ ∃ 𝑒 ∈ 𝐸 { 𝑣 , 𝑘 } ⊆ 𝑒 ) )
7 prcom ⊢ { 𝑘 , 𝑣 } = { 𝑣 , 𝑘 }
8 7 sseq1i ⊢ ( { 𝑘 , 𝑣 } ⊆ 𝑒 ↔ { 𝑣 , 𝑘 } ⊆ 𝑒 )
9 8 rexbii ⊢ ( ∃ 𝑒 ∈ 𝐸 { 𝑘 , 𝑣 } ⊆ 𝑒 ↔ ∃ 𝑒 ∈ 𝐸 { 𝑣 , 𝑘 } ⊆ 𝑒 )
10 id ⊢ ( 𝑣 ∈ 𝑉 → 𝑣 ∈ 𝑉 )
11 eldifi ⊢ ( 𝑘 ∈ ( 𝑉 ∖ { 𝑣 } ) → 𝑘 ∈ 𝑉 )
12 10 11 anim12ci ⊢ ( ( 𝑣 ∈ 𝑉 ∧ 𝑘 ∈ ( 𝑉 ∖ { 𝑣 } ) ) → ( 𝑘 ∈ 𝑉 ∧ 𝑣 ∈ 𝑉 ) )
13 eldifsni ⊢ ( 𝑘 ∈ ( 𝑉 ∖ { 𝑣 } ) → 𝑘 ≠ 𝑣 )
14 13 adantl ⊢ ( ( 𝑣 ∈ 𝑉 ∧ 𝑘 ∈ ( 𝑉 ∖ { 𝑣 } ) ) → 𝑘 ≠ 𝑣 )
15 12 14 jca ⊢ ( ( 𝑣 ∈ 𝑉 ∧ 𝑘 ∈ ( 𝑉 ∖ { 𝑣 } ) ) → ( ( 𝑘 ∈ 𝑉 ∧ 𝑣 ∈ 𝑉 ) ∧ 𝑘 ≠ 𝑣 ) )
16 15 biantrurd ⊢ ( ( 𝑣 ∈ 𝑉 ∧ 𝑘 ∈ ( 𝑉 ∖ { 𝑣 } ) ) → ( ∃ 𝑒 ∈ 𝐸 { 𝑣 , 𝑘 } ⊆ 𝑒 ↔ ( ( ( 𝑘 ∈ 𝑉 ∧ 𝑣 ∈ 𝑉 ) ∧ 𝑘 ≠ 𝑣 ) ∧ ∃ 𝑒 ∈ 𝐸 { 𝑣 , 𝑘 } ⊆ 𝑒 ) ) )
17 9 16 bitr2id ⊢ ( ( 𝑣 ∈ 𝑉 ∧ 𝑘 ∈ ( 𝑉 ∖ { 𝑣 } ) ) → ( ( ( ( 𝑘 ∈ 𝑉 ∧ 𝑣 ∈ 𝑉 ) ∧ 𝑘 ≠ 𝑣 ) ∧ ∃ 𝑒 ∈ 𝐸 { 𝑣 , 𝑘 } ⊆ 𝑒 ) ↔ ∃ 𝑒 ∈ 𝐸 { 𝑘 , 𝑣 } ⊆ 𝑒 ) )
18 6 17 bitrid ⊢ ( ( 𝑣 ∈ 𝑉 ∧ 𝑘 ∈ ( 𝑉 ∖ { 𝑣 } ) ) → ( 𝑘 ∈ ( 𝐺 NeighbVtx 𝑣 ) ↔ ∃ 𝑒 ∈ 𝐸 { 𝑘 , 𝑣 } ⊆ 𝑒 ) )
19 18 ralbidva ⊢ ( 𝑣 ∈ 𝑉 → ( ∀ 𝑘 ∈ ( 𝑉 ∖ { 𝑣 } ) 𝑘 ∈ ( 𝐺 NeighbVtx 𝑣 ) ↔ ∀ 𝑘 ∈ ( 𝑉 ∖ { 𝑣 } ) ∃ 𝑒 ∈ 𝐸 { 𝑘 , 𝑣 } ⊆ 𝑒 ) )
20 19 rabbiia ⊢ { 𝑣 ∈ 𝑉 ∣ ∀ 𝑘 ∈ ( 𝑉 ∖ { 𝑣 } ) 𝑘 ∈ ( 𝐺 NeighbVtx 𝑣 ) } = { 𝑣 ∈ 𝑉 ∣ ∀ 𝑘 ∈ ( 𝑉 ∖ { 𝑣 } ) ∃ 𝑒 ∈ 𝐸 { 𝑘 , 𝑣 } ⊆ 𝑒 }
21 3 20 eqtri ⊢ ( UnivVtx ‘ 𝐺 ) = { 𝑣 ∈ 𝑉 ∣ ∀ 𝑘 ∈ ( 𝑉 ∖ { 𝑣 } ) ∃ 𝑒 ∈ 𝐸 { 𝑘 , 𝑣 } ⊆ 𝑒 }