Metamath Proof Explorer


Theorem ixpeq2

Description: Equality theorem for infinite Cartesian product. (Contributed by NM, 29-Sep-2006)

Ref Expression
Assertion ixpeq2 ( ∀ 𝑥 ∈ 𝐴 𝐵 = 𝐶 → X 𝑥 ∈ 𝐴 𝐵 = X 𝑥 ∈ 𝐴 𝐶 )

Proof

Step Hyp Ref Expression
1 ss2ixp ⊢ ( ∀ 𝑥 ∈ 𝐴 𝐵 ⊆ 𝐶 → X 𝑥 ∈ 𝐴 𝐵 ⊆ X 𝑥 ∈ 𝐴 𝐶 )
2 ss2ixp ⊢ ( ∀ 𝑥 ∈ 𝐴 𝐶 ⊆ 𝐵 → X 𝑥 ∈ 𝐴 𝐶 ⊆ X 𝑥 ∈ 𝐴 𝐵 )
3 1 2 anim12i ⊢ ( ( ∀ 𝑥 ∈ 𝐴 𝐵 ⊆ 𝐶 ∧ ∀ 𝑥 ∈ 𝐴 𝐶 ⊆ 𝐵 ) → ( X 𝑥 ∈ 𝐴 𝐵 ⊆ X 𝑥 ∈ 𝐴 𝐶 ∧ X 𝑥 ∈ 𝐴 𝐶 ⊆ X 𝑥 ∈ 𝐴 𝐵 ) )
4 eqss ⊢ ( 𝐵 = 𝐶 ↔ ( 𝐵 ⊆ 𝐶 ∧ 𝐶 ⊆ 𝐵 ) )
5 4 ralbii ⊢ ( ∀ 𝑥 ∈ 𝐴 𝐵 = 𝐶 ↔ ∀ 𝑥 ∈ 𝐴 ( 𝐵 ⊆ 𝐶 ∧ 𝐶 ⊆ 𝐵 ) )
6 r19.26 ⊢ ( ∀ 𝑥 ∈ 𝐴 ( 𝐵 ⊆ 𝐶 ∧ 𝐶 ⊆ 𝐵 ) ↔ ( ∀ 𝑥 ∈ 𝐴 𝐵 ⊆ 𝐶 ∧ ∀ 𝑥 ∈ 𝐴 𝐶 ⊆ 𝐵 ) )
7 5 6 bitri ⊢ ( ∀ 𝑥 ∈ 𝐴 𝐵 = 𝐶 ↔ ( ∀ 𝑥 ∈ 𝐴 𝐵 ⊆ 𝐶 ∧ ∀ 𝑥 ∈ 𝐴 𝐶 ⊆ 𝐵 ) )
8 eqss ⊢ ( X 𝑥 ∈ 𝐴 𝐵 = X 𝑥 ∈ 𝐴 𝐶 ↔ ( X 𝑥 ∈ 𝐴 𝐵 ⊆ X 𝑥 ∈ 𝐴 𝐶 ∧ X 𝑥 ∈ 𝐴 𝐶 ⊆ X 𝑥 ∈ 𝐴 𝐵 ) )
9 3 7 8 3imtr4i ⊢ ( ∀ 𝑥 ∈ 𝐴 𝐵 = 𝐶 → X 𝑥 ∈ 𝐴 𝐵 = X 𝑥 ∈ 𝐴 𝐶 )