Metamath Proof Explorer


Theorem kqt0

Description: The Kolmogorov quotient is T_0 even if the original topology is not. (Contributed by Mario Carneiro, 25-Aug-2015)

Ref Expression
Assertion kqt0 ( 𝐽 ∈ Top ↔ ( KQ ‘ 𝐽 ) ∈ Kol2 )

Proof

Step Hyp Ref Expression
1 toptopon2 ⊢ ( 𝐽 ∈ Top ↔ 𝐽 ∈ ( TopOn ‘ ∪ 𝐽 ) )
2 eqid ⊢ ( 𝑥 ∈ ∪ 𝐽 ↦ { 𝑦 ∈ 𝐽 ∣ 𝑥 ∈ 𝑦 } ) = ( 𝑥 ∈ ∪ 𝐽 ↦ { 𝑦 ∈ 𝐽 ∣ 𝑥 ∈ 𝑦 } )
3 2 kqt0lem ⊢ ( 𝐽 ∈ ( TopOn ‘ ∪ 𝐽 ) → ( KQ ‘ 𝐽 ) ∈ Kol2 )
4 1 3 sylbi ⊢ ( 𝐽 ∈ Top → ( KQ ‘ 𝐽 ) ∈ Kol2 )
5 t0top ⊢ ( ( KQ ‘ 𝐽 ) ∈ Kol2 → ( KQ ‘ 𝐽 ) ∈ Top )
6 kqtop ⊢ ( 𝐽 ∈ Top ↔ ( KQ ‘ 𝐽 ) ∈ Top )
7 5 6 sylibr ⊢ ( ( KQ ‘ 𝐽 ) ∈ Kol2 → 𝐽 ∈ Top )
8 4 7 impbii ⊢ ( 𝐽 ∈ Top ↔ ( KQ ‘ 𝐽 ) ∈ Kol2 )