Metamath Proof Explorer
Description: A lattice ordering is asymmetric. ( eqss analog.) (Contributed by NM, 8-Oct-2011)
|
|
Ref |
Expression |
|
Hypotheses |
latref.b |
⊢ 𝐵 = ( Base ‘ 𝐾 ) |
|
|
latref.l |
⊢ ≤ = ( le ‘ 𝐾 ) |
|
Assertion |
latasym |
⊢ ( ( 𝐾 ∈ Lat ∧ 𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ) → ( ( 𝑋 ≤ 𝑌 ∧ 𝑌 ≤ 𝑋 ) → 𝑋 = 𝑌 ) ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
latref.b |
⊢ 𝐵 = ( Base ‘ 𝐾 ) |
2 |
|
latref.l |
⊢ ≤ = ( le ‘ 𝐾 ) |
3 |
1 2
|
latasymb |
⊢ ( ( 𝐾 ∈ Lat ∧ 𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ) → ( ( 𝑋 ≤ 𝑌 ∧ 𝑌 ≤ 𝑋 ) ↔ 𝑋 = 𝑌 ) ) |
4 |
3
|
biimpd |
⊢ ( ( 𝐾 ∈ Lat ∧ 𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ) → ( ( 𝑋 ≤ 𝑌 ∧ 𝑌 ≤ 𝑋 ) → 𝑋 = 𝑌 ) ) |