Metamath Proof Explorer


Theorem lcdlkreqN

Description: Colinear functionals have equal kernels. (Contributed by NM, 28-Mar-2015) (New usage is discouraged.)

Ref Expression
Hypotheses lcdlkreq.h ⊢ 𝐻 = ( LHyp ‘ 𝐾 )
lcdlkreq.u ⊢ 𝑈 = ( ( DVecH ‘ 𝐾 ) ‘ 𝑊 )
lcdlkreq.l ⊢ 𝐿 = ( LKer ‘ 𝑈 )
lcdlkreq.c ⊢ 𝐶 = ( ( LCDual ‘ 𝐾 ) ‘ 𝑊 )
lcdlkreq.o ⊢ 0 = ( 0g ‘ 𝐶 )
lcdlkreq.n ⊢ 𝑁 = ( LSpan ‘ 𝐶 )
lcdlkreq.v ⊢ 𝑉 = ( Base ‘ 𝐶 )
lcdlkreq.k ⊢ ( 𝜑 → ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) )
lcdlkreq.i ⊢ ( 𝜑 → 𝐼 ∈ 𝑉 )
lcdlkreq.g ⊢ ( 𝜑 → 𝐺 ∈ ( 𝑁 ‘ { 𝐼 } ) )
lcdlkreq.z ⊢ ( 𝜑 → 𝐺 ≠ 0 )
Assertion lcdlkreqN ( 𝜑 → ( 𝐿 ‘ 𝐺 ) = ( 𝐿 ‘ 𝐼 ) )

Proof

Step Hyp Ref Expression
1 lcdlkreq.h ⊢ 𝐻 = ( LHyp ‘ 𝐾 )
2 lcdlkreq.u ⊢ 𝑈 = ( ( DVecH ‘ 𝐾 ) ‘ 𝑊 )
3 lcdlkreq.l ⊢ 𝐿 = ( LKer ‘ 𝑈 )
4 lcdlkreq.c ⊢ 𝐶 = ( ( LCDual ‘ 𝐾 ) ‘ 𝑊 )
5 lcdlkreq.o ⊢ 0 = ( 0g ‘ 𝐶 )
6 lcdlkreq.n ⊢ 𝑁 = ( LSpan ‘ 𝐶 )
7 lcdlkreq.v ⊢ 𝑉 = ( Base ‘ 𝐶 )
8 lcdlkreq.k ⊢ ( 𝜑 → ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) )
9 lcdlkreq.i ⊢ ( 𝜑 → 𝐼 ∈ 𝑉 )
10 lcdlkreq.g ⊢ ( 𝜑 → 𝐺 ∈ ( 𝑁 ‘ { 𝐼 } ) )
11 lcdlkreq.z ⊢ ( 𝜑 → 𝐺 ≠ 0 )
12 eqid ⊢ ( LFnl ‘ 𝑈 ) = ( LFnl ‘ 𝑈 )
13 eqid ⊢ ( LDual ‘ 𝑈 ) = ( LDual ‘ 𝑈 )
14 eqid ⊢ ( 0g ‘ ( LDual ‘ 𝑈 ) ) = ( 0g ‘ ( LDual ‘ 𝑈 ) )
15 eqid ⊢ ( LSpan ‘ ( LDual ‘ 𝑈 ) ) = ( LSpan ‘ ( LDual ‘ 𝑈 ) )
16 1 2 8 dvhlvec ⊢ ( 𝜑 → 𝑈 ∈ LVec )
17 1 4 7 2 12 8 9 lcdvbaselfl ⊢ ( 𝜑 → 𝐼 ∈ ( LFnl ‘ 𝑈 ) )
18 9 snssd ⊢ ( 𝜑 → { 𝐼 } ⊆ 𝑉 )
19 1 2 13 15 4 7 6 8 18 lcdlsp ⊢ ( 𝜑 → ( 𝑁 ‘ { 𝐼 } ) = ( ( LSpan ‘ ( LDual ‘ 𝑈 ) ) ‘ { 𝐼 } ) )
20 10 19 eleqtrd ⊢ ( 𝜑 → 𝐺 ∈ ( ( LSpan ‘ ( LDual ‘ 𝑈 ) ) ‘ { 𝐼 } ) )
21 1 2 13 14 4 5 8 lcd0v2 ⊢ ( 𝜑 → 0 = ( 0g ‘ ( LDual ‘ 𝑈 ) ) )
22 11 21 neeqtrd ⊢ ( 𝜑 → 𝐺 ≠ ( 0g ‘ ( LDual ‘ 𝑈 ) ) )
23 eldifsn ⊢ ( 𝐺 ∈ ( ( ( LSpan ‘ ( LDual ‘ 𝑈 ) ) ‘ { 𝐼 } ) ∖ { ( 0g ‘ ( LDual ‘ 𝑈 ) ) } ) ↔ ( 𝐺 ∈ ( ( LSpan ‘ ( LDual ‘ 𝑈 ) ) ‘ { 𝐼 } ) ∧ 𝐺 ≠ ( 0g ‘ ( LDual ‘ 𝑈 ) ) ) )
24 20 22 23 sylanbrc ⊢ ( 𝜑 → 𝐺 ∈ ( ( ( LSpan ‘ ( LDual ‘ 𝑈 ) ) ‘ { 𝐼 } ) ∖ { ( 0g ‘ ( LDual ‘ 𝑈 ) ) } ) )
25 12 3 13 14 15 16 17 24 lkrlspeqN ⊢ ( 𝜑 → ( 𝐿 ‘ 𝐺 ) = ( 𝐿 ‘ 𝐼 ) )