Metamath Proof Explorer


Theorem left1s

Description: The left set of 1s is the singleton of 0s . (Contributed by Scott Fenton, 4-Feb-2025)

Ref Expression
Assertion left1s ( L ‘ 1s ) = { 0s }

Proof

Step Hyp Ref Expression
1 leftval ( L ‘ 1s ) = { 𝑥 ∈ ( O ‘ ( bday ‘ 1s ) ) ∣ 𝑥 <s 1s }
2 bday1s ( bday ‘ 1s ) = 1o
3 2 fveq2i ( O ‘ ( bday ‘ 1s ) ) = ( O ‘ 1o )
4 old1 ( O ‘ 1o ) = { 0s }
5 3 4 eqtri ( O ‘ ( bday ‘ 1s ) ) = { 0s }
6 5 rabeqi { 𝑥 ∈ ( O ‘ ( bday ‘ 1s ) ) ∣ 𝑥 <s 1s } = { 𝑥 ∈ { 0s } ∣ 𝑥 <s 1s }
7 breq1 ( 𝑥 = 0s → ( 𝑥 <s 1s ↔ 0s <s 1s ) )
8 7 rabsnif { 𝑥 ∈ { 0s } ∣ 𝑥 <s 1s } = if ( 0s <s 1s , { 0s } , ∅ )
9 6 8 eqtri { 𝑥 ∈ ( O ‘ ( bday ‘ 1s ) ) ∣ 𝑥 <s 1s } = if ( 0s <s 1s , { 0s } , ∅ )
10 0slt1s 0s <s 1s
11 10 iftruei if ( 0s <s 1s , { 0s } , ∅ ) = { 0s }
12 1 9 11 3eqtri ( L ‘ 1s ) = { 0s }