Metamath Proof Explorer
Description: Every ring contains a zero ideal. (Contributed by Stefan O'Rear, 3-Jan-2015) (Proof shortened by AV, 18-Apr-2025)
|
|
Ref |
Expression |
|
Hypotheses |
rnglidl0.u |
⊢ 𝑈 = ( LIdeal ‘ 𝑅 ) |
|
|
rnglidl0.z |
⊢ 0 = ( 0g ‘ 𝑅 ) |
|
Assertion |
lidl0 |
⊢ ( 𝑅 ∈ Ring → { 0 } ∈ 𝑈 ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
rnglidl0.u |
⊢ 𝑈 = ( LIdeal ‘ 𝑅 ) |
2 |
|
rnglidl0.z |
⊢ 0 = ( 0g ‘ 𝑅 ) |
3 |
|
ringrng |
⊢ ( 𝑅 ∈ Ring → 𝑅 ∈ Rng ) |
4 |
1 2
|
rnglidl0 |
⊢ ( 𝑅 ∈ Rng → { 0 } ∈ 𝑈 ) |
5 |
3 4
|
syl |
⊢ ( 𝑅 ∈ Ring → { 0 } ∈ 𝑈 ) |