Metamath Proof Explorer
		
		
		
		Description:  Every ring contains a unit ideal.  (Contributed by Stefan O'Rear, 3-Jan-2015)  (Proof shortened by AV, 18-Apr-2025)
		
			
				
					|  |  | Ref | Expression | 
					
						|  | Hypotheses | rnglidl0.u | ⊢ 𝑈  =  ( LIdeal ‘ 𝑅 ) | 
					
						|  |  | rnglidl1.b | ⊢ 𝐵  =  ( Base ‘ 𝑅 ) | 
				
					|  | Assertion | lidl1 | ⊢  ( 𝑅  ∈  Ring  →  𝐵  ∈  𝑈 ) | 
			
		
		
			
				Proof
				
					
						| Step | Hyp | Ref | Expression | 
						
							| 1 |  | rnglidl0.u | ⊢ 𝑈  =  ( LIdeal ‘ 𝑅 ) | 
						
							| 2 |  | rnglidl1.b | ⊢ 𝐵  =  ( Base ‘ 𝑅 ) | 
						
							| 3 |  | ringrng | ⊢ ( 𝑅  ∈  Ring  →  𝑅  ∈  Rng ) | 
						
							| 4 | 1 2 | rnglidl1 | ⊢ ( 𝑅  ∈  Rng  →  𝐵  ∈  𝑈 ) | 
						
							| 5 | 3 4 | syl | ⊢ ( 𝑅  ∈  Ring  →  𝐵  ∈  𝑈 ) |