Metamath Proof Explorer


Theorem lineq

Description: Solution of a (scalar) linear equation. (Contributed by BJ, 6-Jun-2019)

Ref Expression
Hypotheses lineq.a ⊢ ( 𝜑 → 𝐴 ∈ ℂ )
lineq.b ⊢ ( 𝜑 → 𝐵 ∈ ℂ )
lineq.x ⊢ ( 𝜑 → 𝑋 ∈ ℂ )
lineq.y ⊢ ( 𝜑 → 𝑌 ∈ ℂ )
lineq.n0 ⊢ ( 𝜑 → 𝐴 ≠ 0 )
Assertion lineq ( 𝜑 → ( ( ( 𝐴 · 𝑋 ) + 𝐵 ) = 𝑌 ↔ 𝑋 = ( ( 𝑌 − 𝐵 ) / 𝐴 ) ) )

Proof

Step Hyp Ref Expression
1 lineq.a ⊢ ( 𝜑 → 𝐴 ∈ ℂ )
2 lineq.b ⊢ ( 𝜑 → 𝐵 ∈ ℂ )
3 lineq.x ⊢ ( 𝜑 → 𝑋 ∈ ℂ )
4 lineq.y ⊢ ( 𝜑 → 𝑌 ∈ ℂ )
5 lineq.n0 ⊢ ( 𝜑 → 𝐴 ≠ 0 )
6 1 3 mulcld ⊢ ( 𝜑 → ( 𝐴 · 𝑋 ) ∈ ℂ )
7 6 2 4 addlsub ⊢ ( 𝜑 → ( ( ( 𝐴 · 𝑋 ) + 𝐵 ) = 𝑌 ↔ ( 𝐴 · 𝑋 ) = ( 𝑌 − 𝐵 ) ) )
8 4 2 subcld ⊢ ( 𝜑 → ( 𝑌 − 𝐵 ) ∈ ℂ )
9 1 3 8 5 rdiv ⊢ ( 𝜑 → ( ( 𝐴 · 𝑋 ) = ( 𝑌 − 𝐵 ) ↔ 𝑋 = ( ( 𝑌 − 𝐵 ) / 𝐴 ) ) )
10 7 9 bitrd ⊢ ( 𝜑 → ( ( ( 𝐴 · 𝑋 ) + 𝐵 ) = 𝑌 ↔ 𝑋 = ( ( 𝑌 − 𝐵 ) / 𝐴 ) ) )