Metamath Proof Explorer


Theorem lkrf0

Description: The value of a functional at a member of its kernel is zero. (Contributed by NM, 16-Apr-2014)

Ref Expression
Hypotheses lkrf0.d ⊢ 𝐷 = ( Scalar ‘ 𝑊 )
lkrf0.o ⊢ 0 = ( 0g ‘ 𝐷 )
lkrf0.f ⊢ 𝐹 = ( LFnl ‘ 𝑊 )
lkrf0.k ⊢ 𝐾 = ( LKer ‘ 𝑊 )
Assertion lkrf0 ( ( 𝑊 ∈ 𝑌 ∧ 𝐺 ∈ 𝐹 ∧ 𝑋 ∈ ( 𝐾 ‘ 𝐺 ) ) → ( 𝐺 ‘ 𝑋 ) = 0 )

Proof

Step Hyp Ref Expression
1 lkrf0.d ⊢ 𝐷 = ( Scalar ‘ 𝑊 )
2 lkrf0.o ⊢ 0 = ( 0g ‘ 𝐷 )
3 lkrf0.f ⊢ 𝐹 = ( LFnl ‘ 𝑊 )
4 lkrf0.k ⊢ 𝐾 = ( LKer ‘ 𝑊 )
5 eqid ⊢ ( Base ‘ 𝑊 ) = ( Base ‘ 𝑊 )
6 5 1 2 3 4 ellkr ⊢ ( ( 𝑊 ∈ 𝑌 ∧ 𝐺 ∈ 𝐹 ) → ( 𝑋 ∈ ( 𝐾 ‘ 𝐺 ) ↔ ( 𝑋 ∈ ( Base ‘ 𝑊 ) ∧ ( 𝐺 ‘ 𝑋 ) = 0 ) ) )
7 6 simplbda ⊢ ( ( ( 𝑊 ∈ 𝑌 ∧ 𝐺 ∈ 𝐹 ) ∧ 𝑋 ∈ ( 𝐾 ‘ 𝐺 ) ) → ( 𝐺 ‘ 𝑋 ) = 0 )
8 7 3impa ⊢ ( ( 𝑊 ∈ 𝑌 ∧ 𝐺 ∈ 𝐹 ∧ 𝑋 ∈ ( 𝐾 ‘ 𝐺 ) ) → ( 𝐺 ‘ 𝑋 ) = 0 )