Metamath Proof Explorer


Theorem lmhmlmod1

Description: A homomorphism of left modules has a left module as domain. (Contributed by Stefan O'Rear, 1-Jan-2015)

Ref Expression
Assertion lmhmlmod1 ( 𝐹 ∈ ( 𝑆 LMHom 𝑇 ) → 𝑆 ∈ LMod )

Proof

Step Hyp Ref Expression
1 eqid ( Scalar ‘ 𝑆 ) = ( Scalar ‘ 𝑆 )
2 eqid ( Scalar ‘ 𝑇 ) = ( Scalar ‘ 𝑇 )
3 1 2 lmhmlem ( 𝐹 ∈ ( 𝑆 LMHom 𝑇 ) → ( ( 𝑆 ∈ LMod ∧ 𝑇 ∈ LMod ) ∧ ( 𝐹 ∈ ( 𝑆 GrpHom 𝑇 ) ∧ ( Scalar ‘ 𝑇 ) = ( Scalar ‘ 𝑆 ) ) ) )
4 3 simplld ( 𝐹 ∈ ( 𝑆 LMHom 𝑇 ) → 𝑆 ∈ LMod )