Metamath Proof Explorer


Theorem lplni

Description: Condition implying a lattice plane. (Contributed by NM, 20-Jun-2012)

Ref Expression
Hypotheses lplnset.b ⊢ 𝐵 = ( Base ‘ 𝐾 )
lplnset.c ⊢ 𝐶 = ( ⋖ ‘ 𝐾 )
lplnset.n ⊢ 𝑁 = ( LLines ‘ 𝐾 )
lplnset.p ⊢ 𝑃 = ( LPlanes ‘ 𝐾 )
Assertion lplni ( ( ( 𝐾 ∈ 𝐷 ∧ 𝑌 ∈ 𝐵 ∧ 𝑋 ∈ 𝑁 ) ∧ 𝑋 𝐶 𝑌 ) → 𝑌 ∈ 𝑃 )

Proof

Step Hyp Ref Expression
1 lplnset.b ⊢ 𝐵 = ( Base ‘ 𝐾 )
2 lplnset.c ⊢ 𝐶 = ( ⋖ ‘ 𝐾 )
3 lplnset.n ⊢ 𝑁 = ( LLines ‘ 𝐾 )
4 lplnset.p ⊢ 𝑃 = ( LPlanes ‘ 𝐾 )
5 simpl2 ⊢ ( ( ( 𝐾 ∈ 𝐷 ∧ 𝑌 ∈ 𝐵 ∧ 𝑋 ∈ 𝑁 ) ∧ 𝑋 𝐶 𝑌 ) → 𝑌 ∈ 𝐵 )
6 breq1 ⊢ ( 𝑥 = 𝑋 → ( 𝑥 𝐶 𝑌 ↔ 𝑋 𝐶 𝑌 ) )
7 6 rspcev ⊢ ( ( 𝑋 ∈ 𝑁 ∧ 𝑋 𝐶 𝑌 ) → ∃ 𝑥 ∈ 𝑁 𝑥 𝐶 𝑌 )
8 7 3ad2antl3 ⊢ ( ( ( 𝐾 ∈ 𝐷 ∧ 𝑌 ∈ 𝐵 ∧ 𝑋 ∈ 𝑁 ) ∧ 𝑋 𝐶 𝑌 ) → ∃ 𝑥 ∈ 𝑁 𝑥 𝐶 𝑌 )
9 simpl1 ⊢ ( ( ( 𝐾 ∈ 𝐷 ∧ 𝑌 ∈ 𝐵 ∧ 𝑋 ∈ 𝑁 ) ∧ 𝑋 𝐶 𝑌 ) → 𝐾 ∈ 𝐷 )
10 1 2 3 4 islpln ⊢ ( 𝐾 ∈ 𝐷 → ( 𝑌 ∈ 𝑃 ↔ ( 𝑌 ∈ 𝐵 ∧ ∃ 𝑥 ∈ 𝑁 𝑥 𝐶 𝑌 ) ) )
11 9 10 syl ⊢ ( ( ( 𝐾 ∈ 𝐷 ∧ 𝑌 ∈ 𝐵 ∧ 𝑋 ∈ 𝑁 ) ∧ 𝑋 𝐶 𝑌 ) → ( 𝑌 ∈ 𝑃 ↔ ( 𝑌 ∈ 𝐵 ∧ ∃ 𝑥 ∈ 𝑁 𝑥 𝐶 𝑌 ) ) )
12 5 8 11 mpbir2and ⊢ ( ( ( 𝐾 ∈ 𝐷 ∧ 𝑌 ∈ 𝐵 ∧ 𝑋 ∈ 𝑁 ) ∧ 𝑋 𝐶 𝑌 ) → 𝑌 ∈ 𝑃 )