Metamath Proof Explorer


Theorem lplnneat

Description: No lattice plane is an atom. (Contributed by NM, 15-Jul-2012)

Ref Expression
Hypotheses lplnneat.a ⊢ 𝐴 = ( Atoms ‘ 𝐾 )
lplnneat.p ⊢ 𝑃 = ( LPlanes ‘ 𝐾 )
Assertion lplnneat ( ( 𝐾 ∈ HL ∧ 𝑋 ∈ 𝑃 ) → ¬ 𝑋 ∈ 𝐴 )

Proof

Step Hyp Ref Expression
1 lplnneat.a ⊢ 𝐴 = ( Atoms ‘ 𝐾 )
2 lplnneat.p ⊢ 𝑃 = ( LPlanes ‘ 𝐾 )
3 hllat ⊢ ( 𝐾 ∈ HL → 𝐾 ∈ Lat )
4 eqid ⊢ ( Base ‘ 𝐾 ) = ( Base ‘ 𝐾 )
5 4 2 lplnbase ⊢ ( 𝑋 ∈ 𝑃 → 𝑋 ∈ ( Base ‘ 𝐾 ) )
6 eqid ⊢ ( le ‘ 𝐾 ) = ( le ‘ 𝐾 )
7 4 6 latref ⊢ ( ( 𝐾 ∈ Lat ∧ 𝑋 ∈ ( Base ‘ 𝐾 ) ) → 𝑋 ( le ‘ 𝐾 ) 𝑋 )
8 3 5 7 syl2an ⊢ ( ( 𝐾 ∈ HL ∧ 𝑋 ∈ 𝑃 ) → 𝑋 ( le ‘ 𝐾 ) 𝑋 )
9 6 1 2 lplnnleat ⊢ ( ( 𝐾 ∈ HL ∧ 𝑋 ∈ 𝑃 ∧ 𝑋 ∈ 𝐴 ) → ¬ 𝑋 ( le ‘ 𝐾 ) 𝑋 )
10 9 3expia ⊢ ( ( 𝐾 ∈ HL ∧ 𝑋 ∈ 𝑃 ) → ( 𝑋 ∈ 𝐴 → ¬ 𝑋 ( le ‘ 𝐾 ) 𝑋 ) )
11 8 10 mt2d ⊢ ( ( 𝐾 ∈ HL ∧ 𝑋 ∈ 𝑃 ) → ¬ 𝑋 ∈ 𝐴 )