Metamath Proof Explorer
		
		
		
		Description:  Subgroup sum is idempotent.  (Contributed by NM, 6-Feb-2014)  (Revised by Mario Carneiro, 21-Jun-2014)  (Proof shortened by AV, 27-Dec-2023)
		
			
				
					|  |  | Ref | Expression | 
					
						|  | Hypothesis | lsmub1.p | ⊢  ⊕   =  ( LSSum ‘ 𝐺 ) | 
				
					|  | Assertion | lsmidm | ⊢  ( 𝑈  ∈  ( SubGrp ‘ 𝐺 )  →  ( 𝑈  ⊕  𝑈 )  =  𝑈 ) | 
			
		
		
			
				Proof
				
					
						| Step | Hyp | Ref | Expression | 
						
							| 1 |  | lsmub1.p | ⊢  ⊕   =  ( LSSum ‘ 𝐺 ) | 
						
							| 2 |  | subgsubm | ⊢ ( 𝑈  ∈  ( SubGrp ‘ 𝐺 )  →  𝑈  ∈  ( SubMnd ‘ 𝐺 ) ) | 
						
							| 3 | 1 | smndlsmidm | ⊢ ( 𝑈  ∈  ( SubMnd ‘ 𝐺 )  →  ( 𝑈  ⊕  𝑈 )  =  𝑈 ) | 
						
							| 4 | 2 3 | syl | ⊢ ( 𝑈  ∈  ( SubGrp ‘ 𝐺 )  →  ( 𝑈  ⊕  𝑈 )  =  𝑈 ) |