Metamath Proof Explorer


Theorem lsw0g

Description: The last symbol of an empty word does not exist. (Contributed by Alexander van der Vekens, 11-Nov-2018)

Ref Expression
Assertion lsw0g ( lastS ‘ ∅ ) = ∅

Proof

Step Hyp Ref Expression
1 wrd0 ∅ ∈ Word 𝑉
2 hash0 ( ♯ ‘ ∅ ) = 0
3 lsw0 ( ( ∅ ∈ Word 𝑉 ∧ ( ♯ ‘ ∅ ) = 0 ) → ( lastS ‘ ∅ ) = ∅ )
4 1 2 3 mp2an ( lastS ‘ ∅ ) = ∅