Metamath Proof Explorer


Theorem lt2addsd

Description: Adding both sides of two surreal less-than relations. (Contributed by Scott Fenton, 15-Apr-2025)

Ref Expression
Hypotheses lt2addsd.1 ⊢ ( 𝜑 → 𝐴 ∈ No )
lt2addsd.2 ⊢ ( 𝜑 → 𝐵 ∈ No )
lt2addsd.3 ⊢ ( 𝜑 → 𝐶 ∈ No )
lt2addsd.4 ⊢ ( 𝜑 → 𝐷 ∈ No )
lt2addsd.5 ⊢ ( 𝜑 → 𝐴 <s 𝐶 )
lt2addsd.6 ⊢ ( 𝜑 → 𝐵 <s 𝐷 )
Assertion lt2addsd ( 𝜑 → ( 𝐴 +s 𝐵 ) <s ( 𝐶 +s 𝐷 ) )

Proof

Step Hyp Ref Expression
1 lt2addsd.1 ⊢ ( 𝜑 → 𝐴 ∈ No )
2 lt2addsd.2 ⊢ ( 𝜑 → 𝐵 ∈ No )
3 lt2addsd.3 ⊢ ( 𝜑 → 𝐶 ∈ No )
4 lt2addsd.4 ⊢ ( 𝜑 → 𝐷 ∈ No )
5 lt2addsd.5 ⊢ ( 𝜑 → 𝐴 <s 𝐶 )
6 lt2addsd.6 ⊢ ( 𝜑 → 𝐵 <s 𝐷 )
7 1 2 addscld ⊢ ( 𝜑 → ( 𝐴 +s 𝐵 ) ∈ No )
8 3 2 addscld ⊢ ( 𝜑 → ( 𝐶 +s 𝐵 ) ∈ No )
9 3 4 addscld ⊢ ( 𝜑 → ( 𝐶 +s 𝐷 ) ∈ No )
10 1 3 2 ltadds1d ⊢ ( 𝜑 → ( 𝐴 <s 𝐶 ↔ ( 𝐴 +s 𝐵 ) <s ( 𝐶 +s 𝐵 ) ) )
11 5 10 mpbid ⊢ ( 𝜑 → ( 𝐴 +s 𝐵 ) <s ( 𝐶 +s 𝐵 ) )
12 2 4 3 ltadds2d ⊢ ( 𝜑 → ( 𝐵 <s 𝐷 ↔ ( 𝐶 +s 𝐵 ) <s ( 𝐶 +s 𝐷 ) ) )
13 6 12 mpbid ⊢ ( 𝜑 → ( 𝐶 +s 𝐵 ) <s ( 𝐶 +s 𝐷 ) )
14 7 8 9 11 13 ltstrd ⊢ ( 𝜑 → ( 𝐴 +s 𝐵 ) <s ( 𝐶 +s 𝐷 ) )