Metamath Proof Explorer


Theorem ltdivmul2d

Description: 'Less than' relationship between division and multiplication. (Contributed by Mario Carneiro, 28-May-2016)

Ref Expression
Hypotheses ltmul1d.1 ⊢ ( 𝜑 → 𝐴 ∈ ℝ )
ltmul1d.2 ⊢ ( 𝜑 → 𝐵 ∈ ℝ )
ltmul1d.3 ⊢ ( 𝜑 → 𝐶 ∈ ℝ+ )
Assertion ltdivmul2d ( 𝜑 → ( ( 𝐴 / 𝐶 ) < 𝐵 ↔ 𝐴 < ( 𝐵 · 𝐶 ) ) )

Proof

Step Hyp Ref Expression
1 ltmul1d.1 ⊢ ( 𝜑 → 𝐴 ∈ ℝ )
2 ltmul1d.2 ⊢ ( 𝜑 → 𝐵 ∈ ℝ )
3 ltmul1d.3 ⊢ ( 𝜑 → 𝐶 ∈ ℝ+ )
4 3 rpregt0d ⊢ ( 𝜑 → ( 𝐶 ∈ ℝ ∧ 0 < 𝐶 ) )
5 ltdivmul2 ⊢ ( ( 𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ ∧ ( 𝐶 ∈ ℝ ∧ 0 < 𝐶 ) ) → ( ( 𝐴 / 𝐶 ) < 𝐵 ↔ 𝐴 < ( 𝐵 · 𝐶 ) ) )
6 1 2 4 5 syl3anc ⊢ ( 𝜑 → ( ( 𝐴 / 𝐶 ) < 𝐵 ↔ 𝐴 < ( 𝐵 · 𝐶 ) ) )