Metamath Proof Explorer


Theorem lubub

Description: The LUB of a complete lattice subset is an upper bound. (Contributed by NM, 19-Oct-2011)

Ref Expression
Hypotheses lublem.b ⊢ 𝐵 = ( Base ‘ 𝐾 )
lublem.l ⊢ ≤ = ( le ‘ 𝐾 )
lublem.u ⊢ 𝑈 = ( lub ‘ 𝐾 )
Assertion lubub ( ( 𝐾 ∈ CLat ∧ 𝑆 ⊆ 𝐵 ∧ 𝑋 ∈ 𝑆 ) → 𝑋 ≤ ( 𝑈 ‘ 𝑆 ) )

Proof

Step Hyp Ref Expression
1 lublem.b ⊢ 𝐵 = ( Base ‘ 𝐾 )
2 lublem.l ⊢ ≤ = ( le ‘ 𝐾 )
3 lublem.u ⊢ 𝑈 = ( lub ‘ 𝐾 )
4 1 2 3 lublem ⊢ ( ( 𝐾 ∈ CLat ∧ 𝑆 ⊆ 𝐵 ) → ( ∀ 𝑦 ∈ 𝑆 𝑦 ≤ ( 𝑈 ‘ 𝑆 ) ∧ ∀ 𝑧 ∈ 𝐵 ( ∀ 𝑦 ∈ 𝑆 𝑦 ≤ 𝑧 → ( 𝑈 ‘ 𝑆 ) ≤ 𝑧 ) ) )
5 4 simpld ⊢ ( ( 𝐾 ∈ CLat ∧ 𝑆 ⊆ 𝐵 ) → ∀ 𝑦 ∈ 𝑆 𝑦 ≤ ( 𝑈 ‘ 𝑆 ) )
6 breq1 ⊢ ( 𝑦 = 𝑋 → ( 𝑦 ≤ ( 𝑈 ‘ 𝑆 ) ↔ 𝑋 ≤ ( 𝑈 ‘ 𝑆 ) ) )
7 6 rspccva ⊢ ( ( ∀ 𝑦 ∈ 𝑆 𝑦 ≤ ( 𝑈 ‘ 𝑆 ) ∧ 𝑋 ∈ 𝑆 ) → 𝑋 ≤ ( 𝑈 ‘ 𝑆 ) )
8 5 7 stoic3 ⊢ ( ( 𝐾 ∈ CLat ∧ 𝑆 ⊆ 𝐵 ∧ 𝑋 ∈ 𝑆 ) → 𝑋 ≤ ( 𝑈 ‘ 𝑆 ) )