Metamath Proof Explorer


Theorem mapdcnv11N

Description: The converse of the map defined by df-mapd is one-to-one. (Contributed by NM, 13-Mar-2015) (New usage is discouraged.)

Ref Expression
Hypotheses mapdcnvord.h ⊢ 𝐻 = ( LHyp ‘ 𝐾 )
mapdcnvord.m ⊢ 𝑀 = ( ( mapd ‘ 𝐾 ) ‘ 𝑊 )
mapdcnvord.k ⊢ ( 𝜑 → ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) )
mapdcnvord.x ⊢ ( 𝜑 → 𝑋 ∈ ran 𝑀 )
mapdcnvord.y ⊢ ( 𝜑 → 𝑌 ∈ ran 𝑀 )
Assertion mapdcnv11N ( 𝜑 → ( ( ◡ 𝑀 ‘ 𝑋 ) = ( ◡ 𝑀 ‘ 𝑌 ) ↔ 𝑋 = 𝑌 ) )

Proof

Step Hyp Ref Expression
1 mapdcnvord.h ⊢ 𝐻 = ( LHyp ‘ 𝐾 )
2 mapdcnvord.m ⊢ 𝑀 = ( ( mapd ‘ 𝐾 ) ‘ 𝑊 )
3 mapdcnvord.k ⊢ ( 𝜑 → ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) )
4 mapdcnvord.x ⊢ ( 𝜑 → 𝑋 ∈ ran 𝑀 )
5 mapdcnvord.y ⊢ ( 𝜑 → 𝑌 ∈ ran 𝑀 )
6 1 2 3 4 5 mapdcnvordN ⊢ ( 𝜑 → ( ( ◡ 𝑀 ‘ 𝑋 ) ⊆ ( ◡ 𝑀 ‘ 𝑌 ) ↔ 𝑋 ⊆ 𝑌 ) )
7 1 2 3 5 4 mapdcnvordN ⊢ ( 𝜑 → ( ( ◡ 𝑀 ‘ 𝑌 ) ⊆ ( ◡ 𝑀 ‘ 𝑋 ) ↔ 𝑌 ⊆ 𝑋 ) )
8 6 7 anbi12d ⊢ ( 𝜑 → ( ( ( ◡ 𝑀 ‘ 𝑋 ) ⊆ ( ◡ 𝑀 ‘ 𝑌 ) ∧ ( ◡ 𝑀 ‘ 𝑌 ) ⊆ ( ◡ 𝑀 ‘ 𝑋 ) ) ↔ ( 𝑋 ⊆ 𝑌 ∧ 𝑌 ⊆ 𝑋 ) ) )
9 eqss ⊢ ( ( ◡ 𝑀 ‘ 𝑋 ) = ( ◡ 𝑀 ‘ 𝑌 ) ↔ ( ( ◡ 𝑀 ‘ 𝑋 ) ⊆ ( ◡ 𝑀 ‘ 𝑌 ) ∧ ( ◡ 𝑀 ‘ 𝑌 ) ⊆ ( ◡ 𝑀 ‘ 𝑋 ) ) )
10 eqss ⊢ ( 𝑋 = 𝑌 ↔ ( 𝑋 ⊆ 𝑌 ∧ 𝑌 ⊆ 𝑋 ) )
11 8 9 10 3bitr4g ⊢ ( 𝜑 → ( ( ◡ 𝑀 ‘ 𝑋 ) = ( ◡ 𝑀 ‘ 𝑌 ) ↔ 𝑋 = 𝑌 ) )