Metamath Proof Explorer


Theorem mat1rngiso

Description: There is a ring isomorphism from a ring to the ring of matrices with dimension 1 over this ring. (Contributed by AV, 22-Dec-2019)

Ref Expression
Hypotheses mat1rhmval.k ⊢ 𝐾 = ( Base ‘ 𝑅 )
mat1rhmval.a ⊢ 𝐴 = ( { 𝐸 } Mat 𝑅 )
mat1rhmval.b ⊢ 𝐵 = ( Base ‘ 𝐴 )
mat1rhmval.o ⊢ 𝑂 = ⟨ 𝐸 , 𝐸 ⟩
mat1rhmval.f ⊢ 𝐹 = ( 𝑥 ∈ 𝐾 ↦ { ⟨ 𝑂 , 𝑥 ⟩ } )
Assertion mat1rngiso ( ( 𝑅 ∈ Ring ∧ 𝐸 ∈ 𝑉 ) → 𝐹 ∈ ( 𝑅 RingIso 𝐴 ) )

Proof

Step Hyp Ref Expression
1 mat1rhmval.k ⊢ 𝐾 = ( Base ‘ 𝑅 )
2 mat1rhmval.a ⊢ 𝐴 = ( { 𝐸 } Mat 𝑅 )
3 mat1rhmval.b ⊢ 𝐵 = ( Base ‘ 𝐴 )
4 mat1rhmval.o ⊢ 𝑂 = ⟨ 𝐸 , 𝐸 ⟩
5 mat1rhmval.f ⊢ 𝐹 = ( 𝑥 ∈ 𝐾 ↦ { ⟨ 𝑂 , 𝑥 ⟩ } )
6 1 2 3 4 5 mat1rhm ⊢ ( ( 𝑅 ∈ Ring ∧ 𝐸 ∈ 𝑉 ) → 𝐹 ∈ ( 𝑅 RingHom 𝐴 ) )
7 1 2 3 4 5 mat1f1o ⊢ ( ( 𝑅 ∈ Ring ∧ 𝐸 ∈ 𝑉 ) → 𝐹 : 𝐾 –1-1-onto→ 𝐵 )
8 1 3 isrim ⊢ ( 𝐹 ∈ ( 𝑅 RingIso 𝐴 ) ↔ ( 𝐹 ∈ ( 𝑅 RingHom 𝐴 ) ∧ 𝐹 : 𝐾 –1-1-onto→ 𝐵 ) )
9 6 7 8 sylanbrc ⊢ ( ( 𝑅 ∈ Ring ∧ 𝐸 ∈ 𝑉 ) → 𝐹 ∈ ( 𝑅 RingIso 𝐴 ) )