Metamath Proof Explorer


Theorem minel

Description: A minimum element of a class has no elements in common with the class. (Contributed by NM, 22-Jun-1994) (Proof shortened by JJ, 14-Jul-2021)

Ref Expression
Assertion minel ( ( 𝐴𝐵 ∧ ( 𝐶𝐵 ) = ∅ ) → ¬ 𝐴𝐶 )

Proof

Step Hyp Ref Expression
1 inelcm ( ( 𝐴𝐶𝐴𝐵 ) → ( 𝐶𝐵 ) ≠ ∅ )
2 1 expcom ( 𝐴𝐵 → ( 𝐴𝐶 → ( 𝐶𝐵 ) ≠ ∅ ) )
3 2 necon2bd ( 𝐴𝐵 → ( ( 𝐶𝐵 ) = ∅ → ¬ 𝐴𝐶 ) )
4 3 imp ( ( 𝐴𝐵 ∧ ( 𝐶𝐵 ) = ∅ ) → ¬ 𝐴𝐶 )