Metamath Proof Explorer


Theorem minplycl

Description: The minimal polynomial is a polynomial. (Contributed by Thierry Arnoux, 22-Mar-2025)

Ref Expression
Hypotheses ply1annig1p.o ⊢ 𝑂 = ( 𝐸 evalSub1 𝐹 )
ply1annig1p.p ⊢ 𝑃 = ( Poly1 ‘ ( 𝐸 ↾s 𝐹 ) )
ply1annig1p.b ⊢ 𝐵 = ( Base ‘ 𝐸 )
ply1annig1p.e ⊢ ( 𝜑 → 𝐸 ∈ Field )
ply1annig1p.f ⊢ ( 𝜑 → 𝐹 ∈ ( SubDRing ‘ 𝐸 ) )
ply1annig1p.a ⊢ ( 𝜑 → 𝐴 ∈ 𝐵 )
ply1annig1p.0 ⊢ 0 = ( 0g ‘ 𝐸 )
ply1annig1p.q ⊢ 𝑄 = { 𝑞 ∈ dom 𝑂 ∣ ( ( 𝑂 ‘ 𝑞 ) ‘ 𝐴 ) = 0 }
ply1annig1p.k ⊢ 𝐾 = ( RSpan ‘ 𝑃 )
ply1annig1p.g ⊢ 𝐺 = ( idlGen1p ‘ ( 𝐸 ↾s 𝐹 ) )
minplyval.1 ⊢ 𝑀 = ( 𝐸 minPoly 𝐹 )
Assertion minplycl ( 𝜑 → ( 𝑀 ‘ 𝐴 ) ∈ ( Base ‘ 𝑃 ) )

Proof

Step Hyp Ref Expression
1 ply1annig1p.o ⊢ 𝑂 = ( 𝐸 evalSub1 𝐹 )
2 ply1annig1p.p ⊢ 𝑃 = ( Poly1 ‘ ( 𝐸 ↾s 𝐹 ) )
3 ply1annig1p.b ⊢ 𝐵 = ( Base ‘ 𝐸 )
4 ply1annig1p.e ⊢ ( 𝜑 → 𝐸 ∈ Field )
5 ply1annig1p.f ⊢ ( 𝜑 → 𝐹 ∈ ( SubDRing ‘ 𝐸 ) )
6 ply1annig1p.a ⊢ ( 𝜑 → 𝐴 ∈ 𝐵 )
7 ply1annig1p.0 ⊢ 0 = ( 0g ‘ 𝐸 )
8 ply1annig1p.q ⊢ 𝑄 = { 𝑞 ∈ dom 𝑂 ∣ ( ( 𝑂 ‘ 𝑞 ) ‘ 𝐴 ) = 0 }
9 ply1annig1p.k ⊢ 𝐾 = ( RSpan ‘ 𝑃 )
10 ply1annig1p.g ⊢ 𝐺 = ( idlGen1p ‘ ( 𝐸 ↾s 𝐹 ) )
11 minplyval.1 ⊢ 𝑀 = ( 𝐸 minPoly 𝐹 )
12 1 2 3 4 5 6 7 8 9 10 11 minplyval ⊢ ( 𝜑 → ( 𝑀 ‘ 𝐴 ) = ( 𝐺 ‘ 𝑄 ) )
13 4 fldcrngd ⊢ ( 𝜑 → 𝐸 ∈ CRing )
14 issdrg ⊢ ( 𝐹 ∈ ( SubDRing ‘ 𝐸 ) ↔ ( 𝐸 ∈ DivRing ∧ 𝐹 ∈ ( SubRing ‘ 𝐸 ) ∧ ( 𝐸 ↾s 𝐹 ) ∈ DivRing ) )
15 5 14 sylib ⊢ ( 𝜑 → ( 𝐸 ∈ DivRing ∧ 𝐹 ∈ ( SubRing ‘ 𝐸 ) ∧ ( 𝐸 ↾s 𝐹 ) ∈ DivRing ) )
16 15 simp2d ⊢ ( 𝜑 → 𝐹 ∈ ( SubRing ‘ 𝐸 ) )
17 1 2 3 13 16 6 7 8 ply1annidl ⊢ ( 𝜑 → 𝑄 ∈ ( LIdeal ‘ 𝑃 ) )
18 eqid ⊢ ( Base ‘ 𝑃 ) = ( Base ‘ 𝑃 )
19 eqid ⊢ ( LIdeal ‘ 𝑃 ) = ( LIdeal ‘ 𝑃 )
20 18 19 lidlss ⊢ ( 𝑄 ∈ ( LIdeal ‘ 𝑃 ) → 𝑄 ⊆ ( Base ‘ 𝑃 ) )
21 17 20 syl ⊢ ( 𝜑 → 𝑄 ⊆ ( Base ‘ 𝑃 ) )
22 15 simp3d ⊢ ( 𝜑 → ( 𝐸 ↾s 𝐹 ) ∈ DivRing )
23 2 10 19 ig1pcl ⊢ ( ( ( 𝐸 ↾s 𝐹 ) ∈ DivRing ∧ 𝑄 ∈ ( LIdeal ‘ 𝑃 ) ) → ( 𝐺 ‘ 𝑄 ) ∈ 𝑄 )
24 22 17 23 syl2anc ⊢ ( 𝜑 → ( 𝐺 ‘ 𝑄 ) ∈ 𝑄 )
25 21 24 sseldd ⊢ ( 𝜑 → ( 𝐺 ‘ 𝑄 ) ∈ ( Base ‘ 𝑃 ) )
26 12 25 eqeltrd ⊢ ( 𝜑 → ( 𝑀 ‘ 𝐴 ) ∈ ( Base ‘ 𝑃 ) )