Metamath Proof Explorer
Description: The identity element of a monoid is a left identity. (Contributed by NM, 18-Aug-2011)
|
|
Ref |
Expression |
|
Hypotheses |
mndlrid.b |
⊢ 𝐵 = ( Base ‘ 𝐺 ) |
|
|
mndlrid.p |
⊢ + = ( +g ‘ 𝐺 ) |
|
|
mndlrid.o |
⊢ 0 = ( 0g ‘ 𝐺 ) |
|
Assertion |
mndlid |
⊢ ( ( 𝐺 ∈ Mnd ∧ 𝑋 ∈ 𝐵 ) → ( 0 + 𝑋 ) = 𝑋 ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
mndlrid.b |
⊢ 𝐵 = ( Base ‘ 𝐺 ) |
2 |
|
mndlrid.p |
⊢ + = ( +g ‘ 𝐺 ) |
3 |
|
mndlrid.o |
⊢ 0 = ( 0g ‘ 𝐺 ) |
4 |
1 2 3
|
mndlrid |
⊢ ( ( 𝐺 ∈ Mnd ∧ 𝑋 ∈ 𝐵 ) → ( ( 0 + 𝑋 ) = 𝑋 ∧ ( 𝑋 + 0 ) = 𝑋 ) ) |
5 |
4
|
simpld |
⊢ ( ( 𝐺 ∈ Mnd ∧ 𝑋 ∈ 𝐵 ) → ( 0 + 𝑋 ) = 𝑋 ) |