Metamath Proof Explorer


Theorem mon1pn0

Description: Monic polynomials are not zero. (Contributed by Stefan O'Rear, 28-Mar-2015)

Ref Expression
Hypotheses uc1pn0.p ⊢ 𝑃 = ( Poly1 ‘ 𝑅 )
uc1pn0.z ⊢ 0 = ( 0g ‘ 𝑃 )
mon1pn0.m ⊢ 𝑀 = ( Monic1p ‘ 𝑅 )
Assertion mon1pn0 ( 𝐹 ∈ 𝑀 → 𝐹 ≠ 0 )

Proof

Step Hyp Ref Expression
1 uc1pn0.p ⊢ 𝑃 = ( Poly1 ‘ 𝑅 )
2 uc1pn0.z ⊢ 0 = ( 0g ‘ 𝑃 )
3 mon1pn0.m ⊢ 𝑀 = ( Monic1p ‘ 𝑅 )
4 eqid ⊢ ( Base ‘ 𝑃 ) = ( Base ‘ 𝑃 )
5 eqid ⊢ ( deg1 ‘ 𝑅 ) = ( deg1 ‘ 𝑅 )
6 eqid ⊢ ( 1r ‘ 𝑅 ) = ( 1r ‘ 𝑅 )
7 1 4 2 5 3 6 ismon1p ⊢ ( 𝐹 ∈ 𝑀 ↔ ( 𝐹 ∈ ( Base ‘ 𝑃 ) ∧ 𝐹 ≠ 0 ∧ ( ( coe1 ‘ 𝐹 ) ‘ ( ( deg1 ‘ 𝑅 ) ‘ 𝐹 ) ) = ( 1r ‘ 𝑅 ) ) )
8 7 simp2bi ⊢ ( 𝐹 ∈ 𝑀 → 𝐹 ≠ 0 )