Metamath Proof Explorer


Theorem mon1pn0

Description: Monic polynomials are not zero. (Contributed by Stefan O'Rear, 28-Mar-2015)

Ref Expression
Hypotheses uc1pn0.p 𝑃 = ( Poly1𝑅 )
uc1pn0.z 0 = ( 0g𝑃 )
mon1pn0.m 𝑀 = ( Monic1p𝑅 )
Assertion mon1pn0 ( 𝐹𝑀𝐹0 )

Proof

Step Hyp Ref Expression
1 uc1pn0.p 𝑃 = ( Poly1𝑅 )
2 uc1pn0.z 0 = ( 0g𝑃 )
3 mon1pn0.m 𝑀 = ( Monic1p𝑅 )
4 eqid ( Base ‘ 𝑃 ) = ( Base ‘ 𝑃 )
5 eqid ( deg1𝑅 ) = ( deg1𝑅 )
6 eqid ( 1r𝑅 ) = ( 1r𝑅 )
7 1 4 2 5 3 6 ismon1p ( 𝐹𝑀 ↔ ( 𝐹 ∈ ( Base ‘ 𝑃 ) ∧ 𝐹0 ∧ ( ( coe1𝐹 ) ‘ ( ( deg1𝑅 ) ‘ 𝐹 ) ) = ( 1r𝑅 ) ) )
8 7 simp2bi ( 𝐹𝑀𝐹0 )