Metamath Proof Explorer
Description: A deduction based on modus ponens. (Contributed by NM, 12-Dec-2004)
|
|
Ref |
Expression |
|
Hypotheses |
mp2and.1 |
⊢ ( 𝜑 → 𝜓 ) |
|
|
mp2and.2 |
⊢ ( 𝜑 → 𝜒 ) |
|
|
mp2and.3 |
⊢ ( 𝜑 → ( ( 𝜓 ∧ 𝜒 ) → 𝜃 ) ) |
|
Assertion |
mp2and |
⊢ ( 𝜑 → 𝜃 ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
mp2and.1 |
⊢ ( 𝜑 → 𝜓 ) |
2 |
|
mp2and.2 |
⊢ ( 𝜑 → 𝜒 ) |
3 |
|
mp2and.3 |
⊢ ( 𝜑 → ( ( 𝜓 ∧ 𝜒 ) → 𝜃 ) ) |
4 |
1 3
|
mpand |
⊢ ( 𝜑 → ( 𝜒 → 𝜃 ) ) |
5 |
2 4
|
mpd |
⊢ ( 𝜑 → 𝜃 ) |