Metamath Proof Explorer
Description: An inference based on modus ponens. (Contributed by NM, 3-May-1994)
(Proof shortened by Andrew Salmon, 7-May-2011)
|
|
Ref |
Expression |
|
Hypotheses |
mpanr1.1 |
⊢ 𝜓 |
|
|
mpanr1.2 |
⊢ ( ( 𝜑 ∧ ( 𝜓 ∧ 𝜒 ) ) → 𝜃 ) |
|
Assertion |
mpanr1 |
⊢ ( ( 𝜑 ∧ 𝜒 ) → 𝜃 ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
mpanr1.1 |
⊢ 𝜓 |
2 |
|
mpanr1.2 |
⊢ ( ( 𝜑 ∧ ( 𝜓 ∧ 𝜒 ) ) → 𝜃 ) |
3 |
2
|
anassrs |
⊢ ( ( ( 𝜑 ∧ 𝜓 ) ∧ 𝜒 ) → 𝜃 ) |
4 |
1 3
|
mpanl2 |
⊢ ( ( 𝜑 ∧ 𝜒 ) → 𝜃 ) |