Metamath Proof Explorer


Theorem mptrcl

Description: Reverse closure for a mapping: If the function value of a mapping has a member, the argument belongs to the base class of the mapping. (Contributed by AV, 4-Apr-2020)

Ref Expression
Hypothesis mptrcl.1 𝐹 = ( 𝑥𝐴𝐵 )
Assertion mptrcl ( 𝐼 ∈ ( 𝐹𝑋 ) → 𝑋𝐴 )

Proof

Step Hyp Ref Expression
1 mptrcl.1 𝐹 = ( 𝑥𝐴𝐵 )
2 n0i ( 𝐼 ∈ ( 𝐹𝑋 ) → ¬ ( 𝐹𝑋 ) = ∅ )
3 1 dmmptss dom 𝐹𝐴
4 3 sseli ( 𝑋 ∈ dom 𝐹𝑋𝐴 )
5 ndmfv ( ¬ 𝑋 ∈ dom 𝐹 → ( 𝐹𝑋 ) = ∅ )
6 4 5 nsyl4 ( ¬ ( 𝐹𝑋 ) = ∅ → 𝑋𝐴 )
7 2 6 syl ( 𝐼 ∈ ( 𝐹𝑋 ) → 𝑋𝐴 )