Metamath Proof Explorer
Description: Move the right term in a sum on the RHS to the LHS. (Contributed by David A. Wheeler, 11-Oct-2018)
|
|
Ref |
Expression |
|
Hypotheses |
mvrraddi.1 |
⊢ 𝐵 ∈ ℂ |
|
|
mvrraddi.2 |
⊢ 𝐶 ∈ ℂ |
|
|
mvrraddi.3 |
⊢ 𝐴 = ( 𝐵 + 𝐶 ) |
|
Assertion |
mvrraddi |
⊢ ( 𝐴 − 𝐶 ) = 𝐵 |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
mvrraddi.1 |
⊢ 𝐵 ∈ ℂ |
2 |
|
mvrraddi.2 |
⊢ 𝐶 ∈ ℂ |
3 |
|
mvrraddi.3 |
⊢ 𝐴 = ( 𝐵 + 𝐶 ) |
4 |
3
|
oveq1i |
⊢ ( 𝐴 − 𝐶 ) = ( ( 𝐵 + 𝐶 ) − 𝐶 ) |
5 |
1 2
|
pncan3oi |
⊢ ( ( 𝐵 + 𝐶 ) − 𝐶 ) = 𝐵 |
6 |
4 5
|
eqtri |
⊢ ( 𝐴 − 𝐶 ) = 𝐵 |