Description: If two propositions are not equivalent, then at least one is true. (Contributed by BJ, 19-Apr-2019) (Proof shortened by Wolf Lammen, 19-Jan-2020)
Ref | Expression | ||
---|---|---|---|
Assertion | nbior | ⊢ ( ¬ ( 𝜑 ↔ 𝜓 ) → ( 𝜑 ∨ 𝜓 ) ) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | norbi | ⊢ ( ¬ ( 𝜑 ∨ 𝜓 ) → ( 𝜑 ↔ 𝜓 ) ) | |
2 | 1 | con1i | ⊢ ( ¬ ( 𝜑 ↔ 𝜓 ) → ( 𝜑 ∨ 𝜓 ) ) |