Metamath Proof Explorer


Theorem necom

Description: Commutation of inequality. (Contributed by NM, 14-May-1999)

Ref Expression
Assertion necom ( 𝐴𝐵𝐵𝐴 )

Proof

Step Hyp Ref Expression
1 eqcom ( 𝐴 = 𝐵𝐵 = 𝐴 )
2 1 necon3bii ( 𝐴𝐵𝐵𝐴 )