Metamath Proof Explorer


Theorem negbday

Description: Negation of a surreal number preserves birthday. (Contributed by Scott Fenton, 8-Mar-2025)

Ref Expression
Assertion negbday ( 𝐴 ∈ No → ( bday ‘ ( -us ‘ 𝐴 ) ) = ( bday ‘ 𝐴 ) )

Proof

Step Hyp Ref Expression
1 negbdaylem ⊢ ( 𝐴 ∈ No → ( bday ‘ ( -us ‘ 𝐴 ) ) ⊆ ( bday ‘ 𝐴 ) )
2 negnegs ⊢ ( 𝐴 ∈ No → ( -us ‘ ( -us ‘ 𝐴 ) ) = 𝐴 )
3 2 fveq2d ⊢ ( 𝐴 ∈ No → ( bday ‘ ( -us ‘ ( -us ‘ 𝐴 ) ) ) = ( bday ‘ 𝐴 ) )
4 negscl ⊢ ( 𝐴 ∈ No → ( -us ‘ 𝐴 ) ∈ No )
5 negbdaylem ⊢ ( ( -us ‘ 𝐴 ) ∈ No → ( bday ‘ ( -us ‘ ( -us ‘ 𝐴 ) ) ) ⊆ ( bday ‘ ( -us ‘ 𝐴 ) ) )
6 4 5 syl ⊢ ( 𝐴 ∈ No → ( bday ‘ ( -us ‘ ( -us ‘ 𝐴 ) ) ) ⊆ ( bday ‘ ( -us ‘ 𝐴 ) ) )
7 3 6 eqsstrrd ⊢ ( 𝐴 ∈ No → ( bday ‘ 𝐴 ) ⊆ ( bday ‘ ( -us ‘ 𝐴 ) ) )
8 1 7 eqssd ⊢ ( 𝐴 ∈ No → ( bday ‘ ( -us ‘ 𝐴 ) ) = ( bday ‘ 𝐴 ) )