Metamath Proof Explorer
Description: Contraposition law for unary minus. Deduction form of negcon1 .
(Contributed by David Moews, 28-Feb-2017)
|
|
Ref |
Expression |
|
Hypotheses |
negidd.1 |
⊢ ( 𝜑 → 𝐴 ∈ ℂ ) |
|
|
negcon1d.2 |
⊢ ( 𝜑 → 𝐵 ∈ ℂ ) |
|
Assertion |
negcon1d |
⊢ ( 𝜑 → ( - 𝐴 = 𝐵 ↔ - 𝐵 = 𝐴 ) ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
negidd.1 |
⊢ ( 𝜑 → 𝐴 ∈ ℂ ) |
2 |
|
negcon1d.2 |
⊢ ( 𝜑 → 𝐵 ∈ ℂ ) |
3 |
|
negcon1 |
⊢ ( ( 𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ ) → ( - 𝐴 = 𝐵 ↔ - 𝐵 = 𝐴 ) ) |
4 |
1 2 3
|
syl2anc |
⊢ ( 𝜑 → ( - 𝐴 = 𝐵 ↔ - 𝐵 = 𝐴 ) ) |