Metamath Proof Explorer


Theorem negsf1o

Description: Surreal negation is a bijection. (Contributed by Scott Fenton, 3-Feb-2025)

Ref Expression
Assertion negsf1o -us : No –1-1-onto→ No

Proof

Step Hyp Ref Expression
1 negsf ⊢ -us : No ⟶ No
2 negs11 ⊢ ( ( 𝑥 ∈ No ∧ 𝑦 ∈ No ) → ( ( -us ‘ 𝑥 ) = ( -us ‘ 𝑦 ) ↔ 𝑥 = 𝑦 ) )
3 2 biimpd ⊢ ( ( 𝑥 ∈ No ∧ 𝑦 ∈ No ) → ( ( -us ‘ 𝑥 ) = ( -us ‘ 𝑦 ) → 𝑥 = 𝑦 ) )
4 3 rgen2 ⊢ ∀ 𝑥 ∈ No ∀ 𝑦 ∈ No ( ( -us ‘ 𝑥 ) = ( -us ‘ 𝑦 ) → 𝑥 = 𝑦 )
5 dff13 ⊢ ( -us : No –1-1→ No ↔ ( -us : No ⟶ No ∧ ∀ 𝑥 ∈ No ∀ 𝑦 ∈ No ( ( -us ‘ 𝑥 ) = ( -us ‘ 𝑦 ) → 𝑥 = 𝑦 ) ) )
6 1 4 5 mpbir2an ⊢ -us : No –1-1→ No
7 negsfo ⊢ -us : No –onto→ No
8 df-f1o ⊢ ( -us : No –1-1-onto→ No ↔ ( -us : No –1-1→ No ∧ -us : No –onto→ No ) )
9 6 7 8 mpbir2an ⊢ -us : No –1-1-onto→ No