Metamath Proof Explorer


Theorem negsval2d

Description: Surreal negation in terms of subtraction. (Contributed by Scott Fenton, 15-Apr-2025)

Ref Expression
Hypothesis negsval2d.1 ⊢ ( 𝜑 → 𝐴 ∈ No )
Assertion negsval2d ( 𝜑 → ( -us ‘ 𝐴 ) = ( 0s -s 𝐴 ) )

Proof

Step Hyp Ref Expression
1 negsval2d.1 ⊢ ( 𝜑 → 𝐴 ∈ No )
2 negsval2 ⊢ ( 𝐴 ∈ No → ( -us ‘ 𝐴 ) = ( 0s -s 𝐴 ) )
3 1 2 syl ⊢ ( 𝜑 → ( -us ‘ 𝐴 ) = ( 0s -s 𝐴 ) )