Metamath Proof Explorer


Theorem nesymi

Description: Inference associated with nesym . (Contributed by BJ, 7-Jul-2018) (Proof shortened by Wolf Lammen, 25-Nov-2019)

Ref Expression
Hypothesis nesymi.1 𝐴𝐵
Assertion nesymi ¬ 𝐵 = 𝐴

Proof

Step Hyp Ref Expression
1 nesymi.1 𝐴𝐵
2 1 necomi 𝐵𝐴
3 2 neii ¬ 𝐵 = 𝐴