Metamath Proof Explorer
Description: If x is not free in ph , ps , and ch , then it is not
free in ( ph \/ ps \/ ch ) . (Contributed by Mario Carneiro, 11-Aug-2016)
|
|
Ref |
Expression |
|
Hypotheses |
nf.1 |
⊢ Ⅎ 𝑥 𝜑 |
|
|
nf.2 |
⊢ Ⅎ 𝑥 𝜓 |
|
|
nf.3 |
⊢ Ⅎ 𝑥 𝜒 |
|
Assertion |
nf3or |
⊢ Ⅎ 𝑥 ( 𝜑 ∨ 𝜓 ∨ 𝜒 ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
nf.1 |
⊢ Ⅎ 𝑥 𝜑 |
2 |
|
nf.2 |
⊢ Ⅎ 𝑥 𝜓 |
3 |
|
nf.3 |
⊢ Ⅎ 𝑥 𝜒 |
4 |
|
df-3or |
⊢ ( ( 𝜑 ∨ 𝜓 ∨ 𝜒 ) ↔ ( ( 𝜑 ∨ 𝜓 ) ∨ 𝜒 ) ) |
5 |
1 2
|
nfor |
⊢ Ⅎ 𝑥 ( 𝜑 ∨ 𝜓 ) |
6 |
5 3
|
nfor |
⊢ Ⅎ 𝑥 ( ( 𝜑 ∨ 𝜓 ) ∨ 𝜒 ) |
7 |
4 6
|
nfxfr |
⊢ Ⅎ 𝑥 ( 𝜑 ∨ 𝜓 ∨ 𝜒 ) |