Metamath Proof Explorer


Theorem nf5dv

Description: Apply the definition of not-free in a context. (Contributed by Mario Carneiro, 11-Aug-2016) df-nf changed. (Revised by Wolf Lammen, 18-Sep-2021) (Proof shortened by Wolf Lammen, 13-Jul-2022)

Ref Expression
Hypothesis nf5dv.1 ( 𝜑 → ( 𝜓 → ∀ 𝑥 𝜓 ) )
Assertion nf5dv ( 𝜑 → Ⅎ 𝑥 𝜓 )

Proof

Step Hyp Ref Expression
1 nf5dv.1 ( 𝜑 → ( 𝜓 → ∀ 𝑥 𝜓 ) )
2 ax-5 ( 𝜑 → ∀ 𝑥 𝜑 )
3 2 1 nf5dh ( 𝜑 → Ⅎ 𝑥 𝜓 )