Metamath Proof Explorer


Theorem nfa2

Description: Lemma 24 of Monk2 p. 114. (Contributed by Mario Carneiro, 24-Sep-2016) Remove dependency on ax-12 . (Revised by Wolf Lammen, 18-Oct-2021)

Ref Expression
Assertion nfa2 Ⅎ 𝑥 ∀ 𝑦 ∀ 𝑥 𝜑

Proof

Step Hyp Ref Expression
1 alcom ⊢ ( ∀ 𝑦 ∀ 𝑥 𝜑 ↔ ∀ 𝑥 ∀ 𝑦 𝜑 )
2 nfa1 ⊢ Ⅎ 𝑥 ∀ 𝑥 ∀ 𝑦 𝜑
3 1 2 nfxfr ⊢ Ⅎ 𝑥 ∀ 𝑦 ∀ 𝑥 𝜑