Metamath Proof Explorer


Theorem nfan

Description: If x is not free in ph and ps , then it is not free in ( ph /\ ps ) . (Contributed by Mario Carneiro, 11-Aug-2016) (Proof shortened by Wolf Lammen, 13-Jan-2018) (Proof shortened by Wolf Lammen, 9-Oct-2021)

Ref Expression
Hypotheses nfan.1 𝑥 𝜑
nfan.2 𝑥 𝜓
Assertion nfan 𝑥 ( 𝜑𝜓 )

Proof

Step Hyp Ref Expression
1 nfan.1 𝑥 𝜑
2 nfan.2 𝑥 𝜓
3 1 a1i ( ⊤ → Ⅎ 𝑥 𝜑 )
4 2 a1i ( ⊤ → Ⅎ 𝑥 𝜓 )
5 3 4 nfand ( ⊤ → Ⅎ 𝑥 ( 𝜑𝜓 ) )
6 5 mptru 𝑥 ( 𝜑𝜓 )