Metamath Proof Explorer


Theorem nfci

Description: Deduce that a class A does not have x free in it. (Contributed by Mario Carneiro, 11-Aug-2016)

Ref Expression
Hypothesis nfci.1 ⊢ Ⅎ 𝑥 𝑦 ∈ 𝐴
Assertion nfci Ⅎ 𝑥 𝐴

Proof

Step Hyp Ref Expression
1 nfci.1 ⊢ Ⅎ 𝑥 𝑦 ∈ 𝐴
2 df-nfc ⊢ ( Ⅎ 𝑥 𝐴 ↔ ∀ 𝑦 Ⅎ 𝑥 𝑦 ∈ 𝐴 )
3 2 1 mpgbir ⊢ Ⅎ 𝑥 𝐴