Metamath Proof Explorer


Theorem nfcii

Description: Deduce that a class A does not have x free in it. (Contributed by Mario Carneiro, 11-Aug-2016)

Ref Expression
Hypothesis nfcii.1 ( 𝑦𝐴 → ∀ 𝑥 𝑦𝐴 )
Assertion nfcii 𝑥 𝐴

Proof

Step Hyp Ref Expression
1 nfcii.1 ( 𝑦𝐴 → ∀ 𝑥 𝑦𝐴 )
2 1 nf5i 𝑥 𝑦𝐴
3 2 nfci 𝑥 𝐴